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0.5x^2-1.5x-5=0
a = 0.5; b = -1.5; c = -5;
Δ = b2-4ac
Δ = -1.52-4·0.5·(-5)
Δ = 12.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{12.25}}{2*0.5}=\frac{1.5-\sqrt{12.25}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{12.25}}{2*0.5}=\frac{1.5+\sqrt{12.25}}{1} $
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